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[Mechanics][Circular Motion]: Vertical Circular Motion

Investigate a particle attached to a string moving in a vertical circle. Gravity always points down, tension pulls toward the centre, and the centrifugal force points outward only in the co-rotating (non-inertial) frame. Change the inclination angle, particle mass, angular speed and radius to see how the forces vary.
Speed: v = r|ω|
Centrifugal (rotating frame): Fcf = mrω²
Angle convention: θ = 0° at bottom, 180° at top

Interactive experiment

Motion & force vectorsForce vs inclination angle Otop (180°)bottom (0°)θ = 0°Arrow lengths scaled for display Angle θ (degrees)Force (N)0°180°360° ━ Tension━ Gravity┄ Centrifugal
String tension (inward) Gravity (downward); graph shows inward radial component Centrifugal (outward, rotating frame)
Inclination θ0.0°
Gravity mg9.81 N
Radial gravity (inward +)9.81 N
Centrifugal magnitude32.00 N
Required tension T41.81 N
Linear speed v8.00 m/s
Elapsed time0.00 s
Centripetal acceleration32.00 m/s²
String stateTaut
Set parameters, then start the motion. The angle is measured from the downward vertical.
Model assumption: The plotted motion prescribes a constant angular speed. If the calculated tension is negative, a real string would become slack and the particle would leave the circular path. The animation pauses at the first slack point; it does not simulate subsequent free flight. An external drive would be required to maintain constant ω in general.

Vertical Circular Motion Python Model

Calculate gravity, centrifugal force in the rotating frame and the required tension at different angles. The plot shows the signed inward radial component of gravity, mg cos θ, rather than the constant gravity magnitude mg.

Understanding the forces

1. Gravity

Weight mg always acts vertically downward. Its inward radial component is −mg cos θ, because θ is measured from the bottom. The graph instead displays mg cos θ, the outward radial component of gravity, to make the rotating-frame balance T = mrω² + mg cos θ easy to read.

2. Tension

String tension acts toward the centre. At the bottom, it must provide centripetal force and overcome gravity. At the top, gravity helps supply centripetal force, so less tension is required.

3. Centrifugal force

In a frame rotating with the particle, the centrifugal pseudo-force has magnitude mrω² and points outward. It is not an additional real force in an inertial frame. The inertial-frame equation is T − mg cos θ = mrω².

4. String slackness

A string can pull but cannot push. If mrω² + mg cos θ < 0, the prescribed circle is impossible with a string alone. In particular, to keep the string taut at the top at constant ω, ω ≥ √(g/r).

Challenge: Set r = 2 m and compare ω = 2 rad/s with ω = 4 rad/s. Which can keep the string taut at the top? Predict the minimum required angular speed before checking the graph.